Island Perimeter

  22 Jun 2019

By Wen Xu

leetcode algorithm

Problem description

You are given a map in form of a two-dimensional integer grid where 1 represents land and 0 represents water.

Grid cells are connected horizontally/vertically (not diagonally). The grid is completely surrounded by water, and there is exactly one island (i.e., one or more connected land cells).

The island doesn’t have “lakes” (water inside that isn’t connected to the water around the island). One cell is a square with side length 1. The grid is rectangular, width and height don’t exceed 100. Determine the perimeter of the island.

Example:

Input: [[0,1,0,0], [1,1,1,0], [0,1,0,0], [1,1,0,0]]

Output: 16

Explanation: The perimeter is the 16 yellow stripes in the image below:

Solution

For each cell with 1 (island), we count its 4 neighbors that is water or boarder. After that, we sum it up for all cells with 1. The answer will be perimeter.

Below is my python implementation

class Solution:
    def islandPerimeter(self, grid: List[List[int]]) -> int:
        
        m = len(grid)
        if m == 0:
            return 0
        n = len(grid[0])
        def countEdge(i:int, j:int)->int:
            res = 0
            if i + 1 >= m or grid[i + 1][j] == 0:
                res += 1
            if i - 1 < 0 or grid[i - 1][j] == 0:
                res += 1
            if j + 1 >= n or grid[i][j + 1] == 0:
                res += 1
            if j - 1 < 0 or grid[i][j - 1] == 0:
                res += 1
            return res
        
        ans = 0
        for i in range(m):
            for j in range(n):
                if grid[i][j] == 1:
                    ans += countEdge(i, j)
        return ans
				
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